# Normal distribution ¶

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The distribution is the most important one, also called Normal distribution/Loi normale, Gaussian distribution/Loi gaussienne and Laplace–Gauss distribution/Loi de Laplace-Gauss. The short name is $N(\mu, \sigma^2)$.

• $\mu$ (mu) is the mean ($\mathbb{E}(X)$)
• $\sigma$ (sigma) is the deviation around the mean, known as Standard deviation/écart-type.
• $\sigma^2$ (sigma-square) is the variance ($\mathbb{V}(X)$)

So we have

• The density function is $f_X(x) = {\frac {1}{\sigma {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {x-\mu }{\sigma }}\right)^{2}}$
• $\mathbb{E}(X) = \ \mu$
• $\mathbb{V}(X) = \ \sigma^2$

## Standard normal distribution ¶

The standard normal distribution/loi normale centrée réduite is a normal distribution with $\mu=0$ and $\sigma=1$ giving us $N(0,\ 1)$.

We can create a new variable $Y \sim N(0,\ 1)$ from X with the following formula ()

@ Y \sim \frac{X-\mu}{\sigma} @

• the density function is noted $\phi_X(x)$ (phi) instead of $f_X(x)$
• the cumulative distribution function is noted $\Phi_X(x)$ (Phi) instead of $F_X(x)$

## Standard normal table ¶

If you have $X \sim N(\mu,\ \sigma^2)$, then

$F_X(c) = \mathbb{P}(X \le c) = \mathbb{P}(\frac{X-\mu}{\sigma} \le \frac{c-\mu}{\sigma}) = \phi(\frac{c-\mu}{\sigma})$

You already know some of them, but here is a recap

• $\mathbb{P}(X \le c) \Leftrightarrow \mathbb{P}(X \lt c)$
• $\mathbb{P}(X \ge c) \Leftrightarrow \mathbb{P}(X \gt c)$
• $\mathbb{P}(X \ge c) = 1 - \mathbb{P}(X \le c)$
• $\phi(0.5) = 0$
• $\phi(-x) = 1 - \phi(x)$ (note that even if you can find is a table for $x \lt 0$, you are only given the table with $x \ge 0$ so use this)

And now, you need to use this table to calculate $\phi(x)$. Note that the value at the first line (ex: 0.0) and the first column (ex: 0.00) is the result for $\phi(0.0 + 0.00)$.

This image is an image from the second link ## Inverse cumulative distribution function ¶

We know that

@ \alpha = \mathbb{P}(X \le k) = F_X^{-1}(\alpha) @

so given an alpha, we need to evaluate $F_X^{-1}(\alpha)$ to find the k giving this alpha. For a normal distribution, it's easier since we have

@ F_X^{-1}(\alpha) = \mu + \sigma * \phi^{-1}(\alpha) @

As for $\phi^{-1}(\alpha)$

• if $\alpha \ge 0.5$, you simply need to find the z (sum of line+column) in the table associated with the closest value of $\alpha$
• else $\phi^{-1}(\alpha) = -\phi(1-\alpha)$

For instance, if $\alpha = 0.95$, then you need to search the closest value in the table. We got $\phi(1.64)=0.9495$ and $1.65=0.9505$ giving us $k \in [1.64,1.65]$.

If $\alpha = 0.05$, then we have $\phi^{-1}(0.05) = -\phi(1-0.05) = -\phi(0.95)$ so $k \in [-1.65,-1.64]$.